Hi,
I need to use the -P option to enter in a password, but the password has
a $ in it and I think it's messing it up. I get the error message:
Undefined variable.
Is there a way to make the -P option take whatever argument I want and
not try and interpret it?
And BTW - You're site seems to be wrong for the -P doc:
-----------------------------
Set login password (-S)
Syntax: -PPASS
Use PASS as the user password when accessing protected HTML pages. The
default is to skip protected
pages.
-----------------------------
it's -P, isn't it?
Thanks,
Ali